2,6-Lutidine → HCID 15058662, compound

Participants

Reaction Steps

In a manner similar to Sugihara et al. (Synthesis, p 881 (1978)), the reaction of 8.7 grams (0.043 mole) of 2-fluoroethyl 4-methylsulfinylphenyl ether (Compound 80, prepared by the method of Example 4 using one equivalent of 3-chloroperbenzoic acid), 10.0 ml (0.086 mole) of 2,6-lutidine and 12.2 ml (0.086 mole) of trifluoroacetic anhydride in 160 ml of dry acetonitrile yielded 0.7 gram of 2-fluoroethyl 4-mercaptophenyl ether as an oil.

Provenance & Evidence