2,6-Lutidine → HCID 15058662, compound

HRID 1087891Notes

Reaction equation

HRID 1087891 reaction equation
C[S:2]([C:4]1[CH:9]=[CH:8][C:7]([O:10][CH2:11][CH2:12][F:13])=[CH:6][CH:5]=1)=O.ClC1C=CC=C(C(OO)=O)C=1.N1C(C)=CC=CC=1C.FC(F)(F)C(OC(=O)C(F)(F)F)=O>C(#N)C>[SH:2][C:4]1[CH:5]=[CH:6][C:7]([O:10][CH2:11][CH2:12][F:13])=[CH:8][CH:9]=1

Participants

6

Reactant 4

HCID 79372,6-LutidineHCID 9845Trifluoroacetic anhydrideHCID 70297m-Chloroperbenzoic acidHCID 15058664HCID 15058664, compound

Product 1

HCID 15058662HCID 15058662, compoundYield 9.5%

Reagents, catalysts & solvents 1

HCID 6342AcetonitrileSolvent

Procedure

In a manner similar to Sugihara et al. (Synthesis, p 881 (1978)), the reaction of 8.7 grams (0.043 mole) of 2-fluoroethyl 4-methylsulfinylphenyl ether (Compound 80, prepared by the method of Example 4 using one equivalent of 3-chloroperbenzoic acid), 10.0 ml (0.086 mole) of 2,6-lutidine and 12.2 ml (0.086 mole) of trifluoroacetic anhydride in 160 ml of dry acetonitrile yielded 0.7 gram of 2-fluoroethyl 4-mercaptophenyl ether as an oil.

Workup

  1. customIn a manner similar to Sugihara et al. (Synthesis, p 881 (1978))

Sources & evidence

ORD record
ord-1fa7d3019b5549a398cf40a77308db04
Source dataset
uspto-grants-1990_10
Patent number
US04960884

Reaction notes

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