HRID10959

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID180

Acetone

C3H6O

HCID5049666

Sodium triacetoxyborohydride

C6H10BNaO6

结构：CC(C)(C)OC(=O)NC(=N)c1ccc(CNC(=O)[C@@H]2CCc3ncc(N)c(=O)n32)cc1

HCID145857226

未命名化合物

结构：CC(C)(C)OC(=O)NC(=N)c1ccc(CNC(=O)[C@@H]2CCc3ncc(NCc4ccccc4)c(=O)n32)cc1

HCID145857234

未命名化合物

PRODUCTS

生成物

结构：CC(C)Nc1cnc2n(c1=O)[C@H](C(=O)NCc1ccc(C(=N)NC(=O)OC(C)(C)C)cc1)CC2

HCID145857212

未命名化合物

收率 65%

PROCEDURE

实验过程

Following a procedure similar to that for the preparation of intermediate 1k, intermediate 1j (60 mg, 0.14 mmol), acetone (97.6 mg, 1.68 mmol) and NaBH(OAc)3 (385.7 mg, 1.82 mmol) yielded 43 mg (65%) of intermediate 4a. MS (ESI) 469.1 (M+H+).

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-cd4dd8bceef24f458c22091fe1e77ead
来源数据集: uspto-grants-2006_08
DOI: 10.6084/m9.figshare.5104873.v1
专利: US07094783B2
来源说明: uspto-grants-2006_08

反应 SMILES

[C:1]([O:5][C:6](=[O:38])[NH:7][C:8]([C:10]1[CH:15]=[CH:14][C:13]([CH2:16][NH:17][C:18]([C@H:20]2[N:24]3[C:25](=[O:37])[C:26]([NH:29][CH2:30][C:31]4C=CC=CC=4)=[CH:27][N:28]=[C:23]3[CH2:22][CH2:21]2)=[O:19])=[CH:12][CH:11]=1)=[NH:9])([CH3:4])([CH3:3])[CH3:2].[C:39](OC(=O)NC(C1C=CC(CNC([C@H]2N3C(=O)C(N)=CN=C3CC2)=O)=CC=1)=N)(C)(C)C.CC(C)=O.[BH-](OC(C)=O)(OC(C)=O)OC(C)=O.[Na+]>>[C:1]([O:5][C:6](=[O:38])[NH:7][C:8]([C:10]1[CH:11]=[CH:12][C:13]([CH2:16][NH:17][C:18]([C@H:20]2[N:24]3[C:25](=[O:37])[C:26]([NH:29][CH:30]([CH3:39])[CH3:31])=[CH:27][N:28]=[C:23]3[CH2:22][CH2:21]2)=[O:19])=[CH:14][CH:15]=1)=[NH:9])([CH3:4])([CH3:3])[CH3:2]