Hydrochloric Acid → 2-Propanone, reaction products with phenol
Reaction equation
[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.Cl>CC(C)=O>[CH3:2][C:1]([CH3:6])=[O:7].[C:1]1([OH:7])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1Participants
4
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 95 °C
Procedure
A phenol acetone resin is prepared as follows: 2500 parts of phenol and 25 parts of 37 percent HCl are charged to a reaction vessel, and heated to 45°-50° C. 1305 parts of acetone are added dropwise and allowed to reflux. When all the acetone is introduced, the mixture is refluxed for 90 minutes. Partial vacuum is applied to the reaction vessel equipped for distillation, and the contents are heated to 95° C. Full vacuum is applied and the temperature is raised to 105° C. Then conditions are held until the resin has a clear melting point of 59°-68° C. This melting point is held until the product has an 0.2 gram included plate flow of less than 140 mm. The reaction product is discharged, cooled and broken into particles.
Workup
- temperatureheated to 45°-50° C
- temperatureto reflux
- temperaturethe mixture is refluxed for 90 minutes
- customequipped for distillation
- temperaturethe temperature is raised to 105° C
- temperaturecooled
Sources & evidence
- ORD record
- ord-11d6b75bcadb4ea68850d3cb207fbc44
- Source dataset
- uspto-grants-1982_01
- Patent number
- US04311620
Reaction notes
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