Benzyl Alcohol → Benzyl bromoacetate
Reaction equation
Cl[CH2:2][C:3]([OH:5])=[O:4].[Br-:6].[K+].S(=O)(=O)(O)O.[CH2:13](O)[C:14]1[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1>C1(C)C=CC=CC=1.O>[Br:6][CH2:2][C:3]([O:5][CH2:13][C:14]1[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=1)=[O:4]Participants
7
Reactant 4
Product 1
Reagents, catalysts & solvents 2
Procedure
94.5g (1 mol) of chloroacetic acid, 154.7g (1.3 mol) of potassium bromide, 127.4g (1.3 mol) of c.-sulfuric acid, 75 ml of water, 200g of toluene and 108g (1 mol) of benzylalcohol were used and treated in a similar way as described in Example 3. 214g (93.4% of theory) of benzyl bromoacetate were obtained. Bp. = 145° C/ 4 mmHg. 176.5g (99.7%) of potassium hydrogen sulfate was isolated.
Workup
- additiontreated in a similar way
Sources & evidence
- ORD record
- ord-9343f840880b4756888adaeaffa633dc
- Source dataset
- uspto-grants-1978_10
- Patent number
- US04123443
Reaction notes
Loading…