Hydrochloric Acid → 4-(Benzoylamino)benzoic acid
Reaction equation
[C:1]1([C:7]([NH:9][C:10]2[CH:19]=[CH:18][C:13]([C:14]([O:16]C)=[O:15])=[CH:12][CH:11]=2)=[O:8])[CH:6]=[CH:5][CH:4]=[CH:3][CH:2]=1.[OH-].[K+].Cl>CO>[C:1]1([C:7]([NH:9][C:10]2[CH:11]=[CH:12][C:13]([C:14]([OH:16])=[O:15])=[CH:18][CH:19]=2)=[O:8])[CH:2]=[CH:3][CH:4]=[CH:5][CH:6]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Subsequently, 34.7 g of methyl 4-(phenylcarbonylamino)benzoate was dissolved in 500 mg of methanol and thereto 50 mg of 10% KOH was added. After stirring for 3 hours, the mixture was neutralized with hydrochloric acid and then filtered, to give an acid compound, 4-(phenylcarbonylamino) benzoic acid (26.2 g, 80% yield).
Workup
- filtrationfiltered
Sources & evidence
- ORD record
- ord-62ab27adbd2043008321d0f5b04600d0
- Source dataset
- uspto-grants-2007_10
- Patent number
- US07282522B2
Reaction notes
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