Iodine → 2-Chloro-1-fluoro-4-nitrobenzene
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([N+:8]([O-:10])=[O:9])=[CH:4][CH:3]=1.[Sb](Cl)(Cl)(Cl)(Cl)[Cl:12].II>>[Cl:12][C:3]1[CH:4]=[C:5]([N+:8]([O-:10])=[O:9])[CH:6]=[CH:7][C:2]=1[F:1]Participants
4
Procedure
141 G of 4-fluoronitrobenzene, 7 g of antimony pentachloride and 0.5 g of iodine were charged. The same succeeding procedures as in Example 1 were repeated to obtain 173 g (yield: 99%) of 3-chloro-4-fluoronitrobenzene. Analytical value thereof by gas chromatography was as follows:
Sources & evidence
- ORD record
- ord-9b0eb4a7d2e448afb2ac2ecfba10acd1
- Source dataset
- uspto-grants-1990_02
- Patent number
- US04898996
Reaction notes
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