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HRID1199802

反应详情

EQUATION

反应方程式

HRID 1199802 的结构方程式

REACTANTS

反应物

2
结构：CCOC(=O)[C@@H]1C(=O)NC(=O)C[C@H]1c1ccc(F)cc1
HCID11391819

rel-Ethyl (3R,4S)-4-(4-fluorophenyl)-2,6-dioxo-3-piperidinecarboxylate

C14H14FNO4

2 次

结构：[Al+3].[H-].[H-].[H-].[H-].[Li+]
HCID21226445

未命名化合物

PRODUCTS

生成物

1
结构：OC[C@@H]1CNCC[C@H]1c1ccc(F)cc1
HCID9855829

[4-(4-Fluorophenyl)piperidin-3-yl]methanol

C12H16FNO

收率 22%

AUXILIARIES

试剂、催化剂与溶剂

1
结构：C1CCOC1
溶剂HCID8028

Tetrahydrofuran

C4H8O

PROCEDURE

实验过程

Compound E1 (±)-trans-3-ethoxycarbonyl-4(4'-fluorophenyl)piperidin-2,6-dione (2.0 g) was reduced with lithium aluminium hydride (0.58 g) in refluxing tetrahydrofuran (50 ml) for 4 hours. Work up as described in Example 5 gave the title compound as a solid (0.28 g, 22%).