Phosphorus oxychloride → HCID 54459869, compound
Reaction equation
[CH3:1][S:2][C:3]1[CH:8]=[CH:7][C:6]([C:9]2[NH:10][C:11](=O)[C:12]3[C:17]([CH:18]=2)=[CH:16][CH:15]=[CH:14][CH:13]=3)=[CH:5][CH:4]=1.P(Cl)(Cl)([Cl:22])=O>>[Cl:22][C:11]1[C:12]2[C:17](=[CH:16][CH:15]=[CH:14][CH:13]=2)[CH:18]=[C:9]([C:6]2[CH:7]=[CH:8][C:3]([S:2][CH3:1])=[CH:4][CH:5]=2)[N:10]=1Participants
Procedure
The resulting 3-(4-methylthiophenyl)isoquinolin-1-one (0.73 g) was reacted with phosphorus oxychloride (5 ml) according to the method of Example 10-2, to give 1-chloro-3-(4-methylthiophenyl)isoquinoline. Then, N-ethylpiperazine (10 ml) and potassium carbonate (0.36 g) were added to the resulting product as it was. The resulting mixture were reacted at 100° C. overnight. The reaction solution was evaporated, and the resulting residue were added ethyl acetate and purified water. The ethyl acetate layer was washed with water and brine, and dried over magnesium sulfate. The solvent was evaporated, and the resulting residue was purified by silica gel column chromatography (chloroform/methanol system), to give 0.95 g of the free compound of the title compound as a pale yellow oil.
Sources & evidence
- ORD record
- ord-95c4a449bdb04bfeb8ca7041cd2da851
- Source dataset
- uspto-grants-2002_01
- Patent number
- US06340759B1
Reaction notes
Loading…