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HRID1252037

反应详情

EQUATION

反应方程式

HRID 1252037 的结构方程式

REACTANTS

反应物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：CC(C)=CCCC(C)=CCCC(C)=CCCC(C)=CC(=O)NCCN
HCID53736300

未命名化合物

PRODUCTS

生成物

1
结构：CC(C)=CCCC(C)=CCCC(C)=CCCC(C)=CC(=O)NCCN.Cl
HCID73762859

N-(3,7,11,15-Tetramethyl-2,6,10,14-hexadecatetraenoyl)-ethylenediamine hydrochloride

C22H39ClN2O

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CO
溶剂HCID887

Methanol

CH4O

PROCEDURE

实验过程

Hydrogen chloride gas was passed through a methanol solution of N-(3,7,11,15-tetramethyl-2,6,10,14-hexadecatetraenoyl)-ethylenediamine obtained in Example 9. The solvent was distilled off to afford 6.1 g of the title compound as a brown oil.

WORKUP

后处理

  1. distillationThe solvent was distilled off