HRID1261292

反应详情

EQUATION

反应方程式

HRID 1261292 的结构方程式

PROCEDURE

实验过程

Starting from compound 214 (scheme 46) and following the procedure described above for the synthesis of compound 11 (scheme 2, step 3, example 12), title compound 218 was obtained in 45% yield. MS (m/z) 371.1 (M+H).