Methanol → HCID 136399287, compound

HRID 1263202Notes

Reaction equation

HRID 1263202 reaction equation
[OH:1][C:2]1[C:10]([C:11]([CH3:14])([CH3:13])[CH3:12])=[CH:9][C:5]([C:6]([SH:8])=[S:7])=[CH:4][C:3]=1[C:15]([CH3:18])([CH3:17])[CH3:16].CO.[Zn:21]>[Pt].CCOCC>[OH:1][C:2]1[C:10]([C:11]([CH3:13])([CH3:12])[CH3:14])=[CH:9][C:5]([C:6]([S-:8])=[S:7])=[CH:4][C:3]=1[C:15]([CH3:18])([CH3:17])[CH3:16].[OH:1][C:2]1[C:10]([C:11]([CH3:13])([CH3:12])[CH3:14])=[CH:9][C:5]([C:6]([S-:8])=[S:7])=[CH:4][C:3]=1[C:15]([CH3:18])([CH3:17])[CH3:16].[Zn+2:21]

Participants

6

Procedure

Zinc bis(4-hydroxy-3,5-di-tert.-butyl dithiobenzoate) was prepared as follows. The acid, 4-hydroxy-3,5-di-tert.-butyl dithiobenzoic acid (0.4 g) was dissolved in 15 ml. of methanol. Zinc wire (1.2 cm2) was made the anode and platinum wire (1.4 cm2) was made the cathode. The methanol/acid mixture was placed in a container housing the wire electrodes and 0.1 g of zinc metal was dissolved in 12 hours using 70 ma current and 12 volts. The resulting zinc bis(4-hydroxy-3,5-di-tert.butyl dithiobenzoate) was isolated from ether solution.

Workup

  1. customZinc bis(4-hydroxy-3,5-di-tert.-butyl dithiobenzoate) was prepared
  2. dissolutionwas dissolved in 12 hours

Sources & evidence

ORD record
ord-28218d7a4b0948e3a9af2bb984b737f9
Source dataset
uspto-grants-1984_06
Patent number
US04456509

Reaction notes

Loading…