Hydrogen Bromide → 2-Chloro-3,4-dihydroxybenzaldehyde
Reaction equation
[Cl:1][C:2]1[C:9]([OH:10])=[C:8]([O:11]C)[CH:7]=[CH:6][C:3]=1[CH:4]=[O:5].Br>>[Cl:1][C:2]1[C:9]([OH:10])=[C:8]([OH:11])[CH:7]=[CH:6][C:3]=1[CH:4]=[O:5]Participants
Procedure
2-Chloro-3-hydroxy-4-methoxybenzaldehyde is treated with hydrogen bromide to give 2-chloro-3,4-dihydroxybenzaldehyde which is converted to the methylenedioxy derivative with dibromoethane as described above. The product is condensed with nitromethane and the resulting nitroethylene reduced to give the phenethylamine. This compound is condensed with p-methoxystyrene oxide to give the α-hydroxyphenethylamine intermediate which is treated with an excess of trifluoroacetic acid at room temperature for 18 hours to give 6-chloro-7,8-methylenedioxy-1-phenyl-2,3,4,5-tetrahydro-1H-3-benzazepine. This compound is split using boron trichloride as described above to give 6-chloro-7,8-dihydroxy-1-p-methoxyphenyl-2,3,4,5-tetrahydro-1H-3-benzazepine.
Sources & evidence
- ORD record
- ord-ba64a26adcf848de8b57f4ee748a9954
- Source dataset
- uspto-grants-1981_03
- Patent number
- US04255422
Reaction notes
Loading…