5-Fluorouracil → Tegafur
Reaction equation
[F:1][C:2]1[C:3](=[O:9])[NH:4][C:5](=[O:8])[NH:6][CH:7]=1.[O:10]1[CH:14]=[CH:13][CH2:12][CH2:11]1>N1C=CC=CC=1>[O:10]1[CH2:14][CH2:13][CH2:12][CH:11]1[N:6]1[CH:7]=[C:2]([F:1])[C:3](=[O:9])[NH:4][C:5]1=[O:8]Participants
4
Reagents, catalysts & solvents 1
Procedure
In 100 ml of pyridine were dissolved 13.0 g of 5-fluorouracil and 10.5 g of 2,3-dihydrofuran. To the solution were added 7.5 g of acid clay and the mixture was reacted at 130° C. for 10 hours. The reaction liquid was treated in the same manner as described in Example 21 whereby 1.65 g of 5-fluorouracil were recovered and 14.30 g of 1-(2-tetrahydrofuryl)-5-fluorouracil were obtained. The yield of the end product was 81.9% based on the consumed 5-fluorouracil.
Workup
- customthe mixture was reacted at 130° C. for 10 hours
- customThe reaction liquid
- additionwas treated in the same manner
- customwere recovered
Sources & evidence
- ORD record
- ord-41329383c6b44aea8581b5bfc82a2fbf
- Source dataset
- uspto-grants-1981_03
- Patent number
- US04256885
Reaction notes
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