2-Fluoro-5-nitrobenzoic acid → 5-Amino-2-fluorobenzoic acid
Reaction equation
[F:1][C:2]1[CH:10]=[CH:9][C:8]([N+:11]([O-])=O)=[CH:7][C:3]=1[C:4]([OH:6])=[O:5].[H][H]>C(OCC)(=O)C.[Pd]>[NH2:11][C:8]1[CH:9]=[CH:10][C:2]([F:1])=[C:3]([CH:7]=1)[C:4]([OH:6])=[O:5]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
One hundred eleven g of the above 2-fluoro-5-nitrobenzoic acid (0.60 mole) was dissolved in 1 liter of ethyl acetate. To this solution was added 5 g of 5 percent palladium on charcoal. The mixture was hydrogenated on a Parr apparatus for 24 hours at 20° C. at 50 psi of hydrogen. The theoretical amount of hydrogen was absorbed. The solution was filtered and evaporated to dryness to provide a tan residue of 95.2 g of 5-amino-2-fluorobenzoic acid, a known compound.
Workup
- customThe theoretical amount of hydrogen was absorbed
- filtrationThe solution was filtered
- customevaporated to dryness
Sources & evidence
- ORD record
- ord-336726a0cd0644cd849d87efb4ab74d6
- Source dataset
- uspto-grants-1986_01
- Patent number
- US04565872
Reaction notes
Loading…