Tetrahydrofuran → HCID 12058650, compound
Reaction equation
[Li].[C:2]1([P:8](Cl)[C:9]2[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=2)[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.Br[C:17]1[CH:22]=[CH:21][C:20]([Si:23]([O:30][CH2:31][CH3:32])([O:27][CH2:28][CH3:29])[O:24][CH2:25][CH3:26])=[CH:19][CH:18]=1.[O:33]1CCCC1>>[C:2]1([P:8]([C:9]2[CH:14]=[CH:13][CH:12]=[CH:11][CH:10]=2)([C:17]2[CH:22]=[CH:21][C:20]([Si:23]([O:30][CH2:31][CH3:32])([O:27][CH2:28][CH3:29])[O:24][CH2:25][CH3:26])=[CH:19][CH:18]=2)=[O:33])[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1Participants
Procedure
To the lithium diphenylphosphide solution prepared under nitrogen from lithium (0.6246 g, 0.09 g atom) and diphenylphosphinous chloride (9.92 g, 0.045 mol) in 50 ml dry tetrahydrofuran, 14.5 g (0.045 mol) of 4-bromophenyl triethoxysilane dissolved in 50 ml dry tetrahydrofuran is added during one hour. The blood-red solution turns to a light brown color with the appearance of a small amount of white solid. The solution is filtered under nitrogen, diluted with benzene to precipitate remaining lithium bromide, and refiltered. Analysis of the solution by gasliquid chromatography shows a content of unreacted bromosilane of 3.88 grams (0.0122 mol). Distillation in vacuum gives 4-(diphenylphosphinyl)phenyl triethoxysilane (13 grams, 68.1 percent yield), b.p. 164°-167° C/0.1 mm. The H'NMR spectrum is identical to the material prepared from 4-(diphenylphosphinyl)phenyl magnesium bromide and tetraethyl orthosilicate. The efficiency based upon bromosilane consumed is 93.4 percent.
Workup
- additionis added during one hour
- filtrationThe solution is filtered under nitrogen
- additiondiluted with benzene
- customto precipitate
- distillationDistillation in vacuum
Sources & evidence
- ORD record
- ord-e49b847683304c9f958817f67752c3a3
- Source dataset
- uspto-grants-1976_10
- Patent number
- US03987009
Reaction notes
Loading…