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HRID1290306

反应详情

EQUATION

反应方程式

HRID 1290306 的结构方程式

REACTANTS

反应物

3
结构：C[C@]12CC[C@H]3[C@@H](CCC4=CC(=O)CC[C@@]43C)[C@@H]1CC[C@@H]2O
HCID6013

Testosterone

C19H28O2

结构：CC(C)O[N+](=O)[O-]
HCID15575

Nitric acid, 1-methylethyl ester

C3H7NO3

结构：CC(C)(C)[O-].[K+]
HCID23665647

2-Methyl-2-propanol, potassium salt

C4H9KO

PRODUCTS

生成物

1
结构：C[C@]12CC[C@H]3[C@@H](CCC4=C([N+](=O)[O-])C(=O)CC[C@@]43C)[C@@H]1CC[C@@H]2O
HCID11121164

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

1
结构：CC(C)=O.CCCCCC
溶剂HCID21880519

未命名化合物

PROCEDURE

实验过程

By the method of example 1, testosterone (2.88 g, 10 mM), potassium tert-butoxide (3.40 g, 30 mM) and iso- propylnitrate (1.01 ml) are reacted to yield 17β-hydroxy-4-nitroandrost-4-en-3-one, m.p. 158°-160° C. (acetone-hexane) IR 3533, 1689, 1615(m), 1635 cm-1MS(CI) 334(100%, M+l), 316(50%, M+1-H2 0) 1H-NMR 6 (CDC13) 0.80(3H, S, C1 8-Me), 1.30(s, Clg-Me), 3.66(lH, t, C17 -H). This compound has the following structure: ##STR11##