HRID131971

反应详情

EQUATION

反应方程式

HRID 131971 的结构方程式

PROCEDURE

实验过程

3-(2-fluoro-6-methoxyphenoxy)-nitrotoluene (0.9 g, 65%) was prepared from 2-fluoro-6-methoxyphenol (0.78 g, 5.5 mmol) and 3-fluoro-4-nitrotoluene (0.77 g, 5.0 mmol) following the general procedure A. This compound was reduced to 4-fluoro-2-(2-fluoro-6-methoxyphenoxy)aniline (0.58 g, 72%) following the general procedure C. 1-[2-(2-Fluoro-6-methoxy-phenoxy)-4-methyl-phenyl]-3-thiazol-2-yl-urea (122 mg, 65%) was prepared from 2-(2-fluoro-6-methoxy-phenoxy)-4-methyl-aniline (124 mg, 0.5 mmol) and 2-aminothiazole (60 mg, 0.6 mmol) following the general procedure D.