HRID131973

反应详情

EQUATION

反应方程式

HRID 131973 的结构方程式

PROCEDURE

实验过程

4-(2-Fluoro-6-methoxy-phenoxy)-3-nitrobenzaldehyde (1.0 g, 70%) was prepared from 2-fluoro-6-methoxyphenol (0.78 g, 5.5 mmol) and 4-fluoro-3-nitrobenzaldehyde (0.84 g, 5.0 mmol) following the general procedure A. This was reduced to 5-formyl-2-(2-fluoro-6-methoxy-phenoxy)-aniline (0.57 g, 62%) following general procedure B. 1-[2-(2-Fluoro-6-methoxy-phenoxy)-5-formyl-phenyl]-3-thiazol-2-yl-urea (265 mg, 69%) was prepared from 5-formyl-2-(2-fluoro-6-methoxy-phenoxy)-aniline (261 mg, 1.0 mmol) and 2-aminothiazole (100 mg, 1.0 mmol) following the general procedure D.