Formaldehyde → HCID 69317045, compound

HRID 1350138Notes

Reaction equation

HRID 1350138 reaction equation
[CH:1]([O:4][C:5]1[CH:14]=[C:13]([C:15]([F:18])([F:17])[F:16])[C:12]2[C:7](=[CH:8][CH:9]=[C:10]3[NH:22][C@H:21]([CH3:23])[CH2:20][O:19][C:11]3=2)[N:6]=1)([CH3:3])[CH3:2].C=O.[BH3-][C:27]#N.[Na+]>CC(O)=O>[CH:1]([O:4][C:5]1[CH:14]=[C:13]([C:15]([F:18])([F:17])[F:16])[C:12]2[C:7](=[CH:8][CH:9]=[C:10]3[N:22]([CH3:27])[C@H:21]([CH3:23])[CH2:20][O:19][C:11]3=2)[N:6]=1)([CH3:3])[CH3:2]

Participants

5

Reactant 3

HCID 712FormaldehydeHCID 5003444Sodium cyanoborohydrideHCID 69316792HCID 69316792, compound

Product 1

HCID 69317045HCID 69317045, compoundYield 70%

Reagents, catalysts & solvents 1

HCID 176Acetic AcidSolvent

Procedure

Compound 102 was prepared according to General Method 5 (EXAMPLE 2) from (3R)-3,4-dihydro-8-isopropoxy-3-methyl-10-(trifluoromethyl)-2H-[1,4]oxazino[2,3-f]quinoline (12 mg, 0.04 mmol), 37% formaldehyde solution (0.010 mL, 0.2 mmol, 5 equiv) and NaCNBH3 (10 mg, 0.2 mmol, 5 equiv) in 1 mL AcOH (0.04 M) to afford 9 mg (ca. 70%) of (R)-3,4-dihydro-8-isopropoxy-3,4-dimethyl-10-(trifluoromethyl)-2H-[1,4]oxazino[2,3-f]quinoline. This material (9 mg, 0.03 mmol) was taken on directly according to General Method 4 (EXAMPLE 1) by treatment with 3 mL acetic acid and 3 mL concentrated HCl and heated at 90° C. for 4 h to afford 7 mg (89%) of Compound 102 after flash chromatography (3:1 hexanes:EtOAc to 1:1 hexanes:EtOAc, gradient elution). 1H NMR (500 MHz, CDCl3) δ 11.90 (bs, 1H), 7.12 (s, 1H), 7.01 (d, J=9.3, 1H), 6.96 (d, J=9.3, 1H), 4.19 (dd, J=10.7, 2.9, 1H), 4.11 (dd, J=10.7, 3.7, 1H), 3.43 (m, 1H), 2.93 (s, 3H), 1.21 (d, J=6.8, 3H)

Sources & evidence

ORD record
ord-dd12f12181d242d2b972885ec7c68c7c
Source dataset
uspto-grants-2007_05
Patent number
US07214690B2

Reaction notes

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