HRID1359873

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID7183063

未命名化合物

结构：CN(C)C(On1nnc2cccnc21)=[N+](C)C.F[P-](F)(F)(F)(F)F

HCID9886157

Methanaminium, N-((dimethylamino)(3H-1,2,3-triazolo(4,5-b)pyridin-3-yloxy)methylene)-N-methyl-, hexafluorophosphate(1-) (1:1)

C10H15F6N6OP

$结构：Cc1[nH]c(/C=C2\C(=O)Nc3ccc(S(=O)(=O)Cc4c(Cl)cccc4Cl)cc32)c(C)c1CCC(=O)O$

HCID59077622

未命名化合物

PRODUCTS

生成物

$结构：Cc1[nH]c(/C=C2\C(=O)Nc3ccc(S(=O)(=O)Cc4c(Cl)cccc4Cl)cc32)c(C)c1CCC(=O)N1CCC[C@@H](CN2CCCC2)C1$

HCID59077761

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID6228

N,N-Dimethylformamide

C3H7NO

PROCEDURE

实验过程

A mixture of 3-{5-[5-(2,6-dichloro-phenylmethanesulfonyl)-2-oxo-1,2-dihydro-indol-(3Z)-ylidenemethyl]-2,4-dimethyl-1H-pyrrol-3-yl}-propionic acid (267 mg), HATU (1.2 eq.), (R)-3-pyrrolidin-1-ylmethyl-piperidine (2×) in DMF (2.5 mL) was stirred at rt for 2 hours. The reaction was concentrated, diluted with DCM, washed with water (2×), sodium carbonate (2×), dried and concentrated. The residue was purified on a silica gel column to give 145 mg of the titled compound as a yellow solid.

WORKUP

后处理

concentrationThe reaction was concentrated
additiondiluted with DCM
washwashed with water (2×), sodium carbonate (2×)
customdried
concentrationconcentrated
customThe residue was purified on a silica gel column

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-c0e62caaae424c7e85d02cc6e358b786
来源数据集: uspto-grants-2003_07
DOI: 10.6084/m9.figshare.5104873.v1
专利: US06599902B2
来源说明: uspto-grants-2003_07

反应 SMILES

[Cl:1][C:2]1[CH:7]=[CH:6][CH:5]=[C:4]([Cl:8])[C:3]=1[CH2:9][S:10]([C:13]1[CH:14]=[C:15]2[C:19](=[CH:20][CH:21]=1)[NH:18][C:17](=[O:22])/[C:16]/2=[CH:23]\[C:24]1[NH:28][C:27]([CH3:29])=[C:26]([CH2:30][CH2:31][C:32](O)=[O:33])[C:25]=1[CH3:35])(=[O:12])=[O:11].CN(C(ON1N=NC2C=CC=NC1=2)=[N+](C)C)C.F[P-](F)(F)(F)(F)F.[N:60]1([CH2:65][C@@H:66]2[CH2:71][CH2:70][CH2:69][NH:68][CH2:67]2)[CH2:64][CH2:63][CH2:62][CH2:61]1>CN(C=O)C>[Cl:1][C:2]1[CH:7]=[CH:6][CH:5]=[C:4]([Cl:8])[C:3]=1[CH2:9][S:10]([C:13]1[CH:14]=[C:15]2[C:19](=[CH:20][CH:21]=1)[NH:18][C:17](=[O:22])/[C:16]/2=[CH:23]\[C:24]1[NH:28][C:27]([CH3:29])=[C:26]([CH2:30][CH2:31][C:32](=[O:33])[N:68]2[CH2:69][CH2:70][CH2:71][C@@H:66]([CH2:65][N:60]3[CH2:61][CH2:62][CH2:63][CH2:64]3)[CH2:67]2)[C:25]=1[CH3:35])(=[O:11])=[O:12]