4-Fluoro-2-nitrophenol → 2-Amino-4-fluorophenol
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([OH:8])=[C:4]([N+:9]([O-])=O)[CH:3]=1>CO.[C].[Pd]>[NH2:9][C:4]1[CH:3]=[C:2]([F:1])[CH:7]=[CH:6][C:5]=1[OH:8]Participants
4
Reagents, catalysts & solvents 2
Procedure
In methanol (20 ml) was dissolved 4-fluoro-2-nitrophenol (1.00 g, 6.37 mmol). To the resulting solution was added 10% palladium-carbon (0.20 g, 20 wt %). The resulting mixture was subjected to catalytic hydrogenation under stirring for 2 days. After the reaction mixture was filtered through Celite to remove the catalyst, the filtrate was distilled under reduced pressure to remove the solvent, whereby 2-amino-4-fluorophenol (850 mg, 100%) was obtained as a reddish brown solid.
Workup
- filtrationAfter the reaction mixture was filtered through Celite
- customto remove the catalyst
- distillationthe filtrate was distilled under reduced pressure
- customto remove the solvent
Sources & evidence
- ORD record
- ord-75dac2c756b745fcb48982b3e3794499
- Source dataset
- uspto-grants-2007_01
- Patent number
- US07157487B2
Reaction notes
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