Hydrogen Bromide → Citalopram Hydrobromide
Reaction equation
[CH3:1][N:2]([CH2:4][CH2:5][CH2:6][C:7]1([C:18]2[CH:19]=[CH:20][C:21]([F:24])=[CH:22][CH:23]=2)[O:15][CH2:14][C:13]2[CH:12]=[C:11]([C:16]#[N:17])[CH:10]=[CH:9][C:8]1=2)[CH3:3].[BrH:25]>CC(C)=O>[CH3:1][N:2]([CH2:4][CH2:5][CH2:6][C:7]1([C:18]2[CH:23]=[CH:22][C:21]([F:24])=[CH:20][CH:19]=2)[O:15][CH2:14][C:13]2[CH:12]=[C:11]([C:16]#[N:17])[CH:10]=[CH:9][C:8]1=2)[CH3:3].[BrH:25]Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 1
Procedure
To a solution of 7.1 g of citalopram base in 35 ml of dichloromethane a solution of 7 g of sodium metabisulphite in 25 ml of deionized water is added. The pH of the mixture is brought to 6.0 by addition of 5% aqueous ammonium hydroxide, then the organic phase is discarded, the aqueous one is brought to pH=7.0 by addition of sodium bicarbonate and extracted with 2×10 ml of toluene. The organic phases are concentrated under vacuum at 50° C. to give 6.9 g of citalopram base with purity (HPLC)=99.8% (area). These 6.9 g of citalopram base are dissolved in 30 ml of acetone and 48% HBr is added to the solution to a pH of 4÷5. The obtained solution is evaporated under vacuum and the residue is crystallized with acetone to give 5.6 g of citalopram hydrobromide with purity (HPLC)=99.4% (area) and m.p. 185÷187° C.
Workup
- customThe obtained solution is evaporated under vacuum
- customthe residue is crystallized with acetone
Sources & evidence
- ORD record
- ord-0afba983b97b427bb5fb104868c491fc
- Source dataset
- uspto-grants-2007_01
- Patent number
- US07166729B2
Reaction notes
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