Water → 4-isopropyl-5-iodo-1H-imidazole
Reaction equation
I[C:2]1[NH:3][C:4]([I:10])=[C:5]([CH:7]([CH3:9])[CH3:8])[N:6]=1.O.S([O-])([O-])=O.[Na+].[Na+]>C(O)C>[CH:7]([C:5]1[N:6]=[CH:2][NH:3][C:4]=1[I:10])([CH3:9])[CH3:8]Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Conditions
- Temperature
- 85 °C
Procedure
In 240 ml of ethanol was dissolved 48.1 g (0.144 mol)of 2,5-diiodo-4-isopropyl-1H-imidazole (7), followed by addition of 240 ml of water and 20.1 g (0.159 mol)of sodium sulfite. The mixture was heated at 85° C. for 35 minutes. This reaction mixture was concentrated and extracted with methylene chloride and the extract was washed with water and dried over sodium sulfate. After filtration, the solvent was distilled off under reduced pressure and the residue was washed with ethyl acetate-diisopropyl ether and filtered to provide 26.9 g (yield 86%)of 4-isopropyl-5-iodo-1H-imidazole (4b).
Workup
- concentrationThis reaction mixture was concentrated
- extractionextracted with methylene chloride
- washthe extract was washed with water
- dry with materialdried over sodium sulfate
- filtrationAfter filtration
- distillationthe solvent was distilled off under reduced pressure
- washthe residue was washed with ethyl acetate-diisopropyl ether
- filtrationfiltered
Sources & evidence
- ORD record
- ord-081faacc0ad54bac935b09282f7b9505
- Source dataset
- uspto-grants-1999_06
- Patent number
- US05910506
Reaction notes
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