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HuagongsheHuagongshe Chemistry Print Report · For research reference only
HRID 1418061Generated: November 3, 2026

Lithium hydride → 4-(4-Ethoxyphenyl)-2-fluoro-4-methylpent-2-enol

https://huagongshe.com/reaction/1418061

Reaction equation

Participants

RoleNameHCIDCharge
ReactantLithium hydrideHCID 62714—
ReactantMethyl 2-fluoro-4-(4-ethoxy-phenyl)-4-methylpent-2-enoateHCID 54191630—
SolventDiethyl EtherHCID 3283—
Product4-(4-Ethoxyphenyl)-2-fluoro-4-methylpent-2-enolHCID 5369215390%

Reaction Steps

The method of Example 6 was repeated using methyl 2-fluoro-4-(4-ethoxy-phenyl)-4-methylpent-2-enoate (Example 4) (0.2 g), diethyl ether (15 ml) and lithium hydride (0.1 g) to yield the title compound (0.16 g, 90%).

Provenance & Evidence

DOI10.6084/m9.figshare.5104873.v1
Patent numberUS05880162
Source datasetuspto-grants-1999_03
ORD IDord-447b5bac63ac4362b88372f90bb8017a
Source noteuspto-grants-1999_03