Ethyl Acetate → 2,5-Difluoroaniline
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([F:8])=[CH:4][C:3]=1[N+:9]([O-])=O.CC(=O)OCC>CO.[Pd]>[F:1][C:2]1[CH:7]=[CH:6][C:5]([F:8])=[CH:4][C:3]=1[NH2:9]Participants
5
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Conditions
- Temperature
- 20 °C
Procedure
To a solution of 1,4-difluoro-2-nitrobenzene (500 mg, 3.14 mmol) in MeOH (20 mL) was added Pd/C (66.9 mg, 0.629 mmol) in portions. Then the mixture was stirred under a H2 atmosphere at 20° C. for 1 h. After TLC (PE/EA=3/1) analysis showed the starting material had disappeared, the mixture was filtered. The filtrate was concentrated to give the desired product 2,5-difluoroaniline (338 mg, 2.61 mmol, 83% yield). 1H NMR: (400 MHz, CDCl3) δ 6.94-6.88 (m, 1H), 6.50-6.46 (m, 1H), 6.40-6.31 (m, 1H), 3.82 (br. s., 2H).
Workup
- filtrationthe mixture was filtered
- concentrationThe filtrate was concentrated
Sources & evidence
- ORD record
- ord-6e83b218022f478e8b320c7835694df7
- Source dataset
- uspto-grants-2015_01
- Patent number
- US08937071B2
Reaction notes
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