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HRID1436041

反应详情

EQUATION

反应方程式

HRID 1436041 的结构方程式

REACTANTS

反应物

4
结构：CN(C(=O)OC(C)(C)C)C1CCNC1
HCID2761404

tert-Butyl methyl(pyrrolidin-3-yl)carbamate

C10H20N2O2

结构：CN(C(=O)OC(C)(C)C)[C@H]1CCNC1
HCID7171888

tert-Butyl methyl[(3S)-pyrrolidin-3-yl]carbamate

C10H20N2O2

结构：O=S(=O)(Cl)c1cccc2cncc(Br)c12
HCID14580058

4-Bromo-5-isoquinolinesulfonyl chloride

C9H5BrClNO2S

结构：O=S(=O)(Cl)c1cccc2cncc(Cl)c12
HCID22121908

4-Chloroisoquinoline-5-sulfonyl chloride

C9H5Cl2NO2S

PRODUCTS

生成物

2
结构：Cl
HCID313

Hydrochloric Acid

ClH

结构：CN(C(=O)OC(C)(C)C)[C@H]1CCN(S(=O)(=O)c2cccc3cncc(Cl)c23)C1
HCID67243150

未命名化合物

PROCEDURE

实验过程

That is, (S)-3-[N-(tert-butoxycarbonyl)-N-methylamino]-1-(4-chloro-5-isoquinolinesulfonyl)pyrrolidine (Intermediate 21a) was prepared by using 4-chloro-5-isoquinolinesulfonyl chloride and (S)-3-[N-(tert-butoxycarbonyl)-N-methylamino]pyrrolidine in the method of Example 31, Step A instead of 4-bromo-5-isoquinolinesulfonyl chloride and 3-[N-(tert-butoxycarbonyl)-N-methylamino]pyrrolidine, respectively, and then used in the method of Example 31, Step B in a similar manner to obtain the compound of Example 19-3 as hydrochloride.