Phosphorus tribromide → HCID 54251209, compound

HRID 1449208Notes

Reaction equation

HRID 1449208 reaction equation
[CH2:1]1[O:9][C:8]2[CH:7]=[CH:6][C:5]([CH2:10][CH2:11][CH:12]([CH:14]3[CH2:16][CH2:15]3)O)=[CH:4][C:3]=2[O:2]1.P(Br)(Br)[Br:18].[Br-].[Li+]>[Br-].[Zn+2].[Br-]>[CH2:1]1[O:9][C:8]2[CH:7]=[CH:6][C:5]([CH2:10][CH2:11][CH:12]=[CH:14][CH2:15][CH2:16][Br:18])=[CH:4][C:3]=2[O:2]1

Participants

5

Reactant 3

HCID 24614Phosphorus tribromideHCID 82050Lithium BromideHCID 23455710HCID 23455710, compound

Product 1

HCID 54251209HCID 54251209, compound

Reagents, catalysts & solvents 1

HCID 10421208Zinc bromideCatalyst

Procedure

6-(3,4-Methylenedioxyphenyl)-3-hexenyl bromide [V; Ar is 3,4-methylenedioxyphenyl, R is H] was prepared from 11.5 g. of 2-(3,4-methylenedioxyphenyl)ethyl cyclopropyl carbinol (Preparation B2), 12 g. of phosphorus tribromide, 10 g. of lithium bromide and 12.7 g. of zinc bromide according to the procedure given above in Preparation C1, affording 12.5 g. of product as an oil.

Workup

  1. customaffording 12.5 g

Sources & evidence

ORD record
ord-9c43e9dab9714b55a38da3ea8d5c8013
Source dataset
uspto-grants-1980_02
Patent number
US04189500

Reaction notes

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