Methanol → 4-(2-Methoxyethyl)phenol
Reaction equation
[OH:1][C:2]1[CH:10]=[CH:9][C:5]([CH2:6][CH2:7][OH:8])=[CH:4][CH:3]=1.[CH3:11]O>>[CH3:11][O:8][CH2:7][CH2:6][C:5]1[CH:9]=[CH:10][C:2]([OH:1])=[CH:3][CH:4]=1Participants
3
Reactant 2
Product 1
Conditions
- Temperature
- 100 °C
Procedure
A solution of twenty (20) grams 4-hydroxyphenethyl alcohol in 150 ml methanol containing 36.75 grams sulfuric acid (catalyst) were loaded into a 300 cc autoclave. The autoclave was then sealed and purged with nitrogen and pressurized with nitrogen gas to 500 psig. The autoclave was then heated to 100° C. with stirring at 300 rpm. The reaction was allowed to take place for approximately twenty-four (24) hours. The autoclave was then purged with nitrogen, cooled to 5° C., and vented slowly. The resultant material was 90 ml of a dark, greenish-black solution. An aliquot was treated with base and analyzed by gas chromatography (GC). A 40% yield of 4-(2'-methoxyethyl)phenol was obtained.
Workup
- customThe autoclave was then sealed
- custompurged with nitrogen
- customThe autoclave was then purged with nitrogen
- temperaturecooled to 5° C.
- additionAn aliquot was treated with base
Sources & evidence
- ORD record
- ord-7aebc78558d8449dba57076441235bdf
- Source dataset
- uspto-grants-1997_02
- Patent number
- US05602285
Reaction notes
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