HRID1451889

反应详情

EQUATION

反应方程式

HRID 1451889 的结构方程式

PROCEDURE

实验过程

The procedure similar to that described in Example 1 was repeated, except that 300 mg (0.67 mmol) of Compound 100 was used in place of Compound 24 and propyl iodide was used in place of methyl iodide. As a result, 238.8 mg (yield: 73%) of Compound 58 was obtained as white crystals.