HRID1451910
反应详情
EQUATION
反应方程式
REACTANTS
反应物
PRODUCTS
生成物
PROCEDURE
实验过程
The procedure similar to that described in Example 1 was repeated, except that 100.0 mg (0.22 mmol) of Compound 90 obtained in Example 80 was used in place of Compound 24 and propyl iodide was used in place of methyl iodide. As a result, 69.0 mg (yield: 64%) of Compound 92 was obtained as white crystals.