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HRID1462420

反应详情

EQUATION

反应方程式

HRID 1462420 的结构方程式

REACTANTS

反应物

3
结构：CCOC(=O)CBr
HCID7748

Ethyl bromoacetate

C4H7BrO2

结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：O=C(NCC(=O)c1cccs1)c1ccccc1
HCID13105421

未命名化合物

PRODUCTS

生成物

1
结构：CCOC(=O)CC(NC(=O)c1ccccc1)C(=O)c1cccs1
HCID13105424

未命名化合物

收率 63.5%

PROCEDURE

实验过程

4.0 g of N-benzoyl-N-[(2-thienylcarbonyl)methyl]amine, one g of 50% sodium hydride and 2.7 g of ethyl bromoacetate are treated in the same manner as described in Preparation 1-(4). 3.4 g of ethyl 3-benzoylamino-3-(2-thienylcarbonyl)propionate are obtained.

WORKUP

后处理

  1. customas described in Preparation 1-(4)