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HRID1462422

反应详情

EQUATION

反应方程式

HRID 1462422 的结构方程式

REACTANTS

反应物

3
结构：CCOC(=O)CBr
HCID7748

Ethyl bromoacetate

C4H7BrO2

结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：O=C(CNC(=O)c1ccccc1)c1ccsc1
HCID13105427

未命名化合物

PRODUCTS

生成物

1
结构：CCOC(=O)CC(NC(=O)c1ccccc1)C(=O)c1ccsc1
HCID13105431

未命名化合物

收率 68%

PROCEDURE

实验过程

4.7 g of N-benzoyl-N-[(3-thienylcarbonyl)methyl]amine, 1.1 g of 50% sodium hydride and 3.9 g of ethyl bromoacetate are treated in the same manner as described in Preparation 1-(4). 4.2 g of ethyl 3-benzoylamino-3-(3-thienylcarbonyl)propionate are thereby obtained.

WORKUP

后处理

  1. customas described in Preparation 1-(4)