HRID1464382

反应详情

EQUATION

反应方程式

HRID 1464382 的结构方程式

PROCEDURE

实验过程

In analogy to the procedure of Example XIV, the title compound is prepared from 16 g (0.082 mol) of methyl 3-methoxy-4-hydroxyphenylacetate, 14.5 g (0.082 mol) of 2-chloromethylquinoline and 3.28 g (0.082 mol) of sodium hydroxide.