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HRID1465188

反应详情

EQUATION

反应方程式

HRID 1465188 的结构方程式

REACTANTS

反应物

2
结构：CI
HCID6328

Methyl iodide

CH3I

结构：CCOC(=O)c1nn(-c2ccc(F)cc2)cc1O
HCID730292

Ethyl 1-(4-fluorophenyl)-4-hydroxy-1H-pyrazole-3-carboxylate

C12H11FN2O3

PRODUCTS

生成物

1
结构：CCOC(=O)c1nn(-c2ccc(F)cc2)cc1OC
HCID66611500

未命名化合物

PROCEDURE

实验过程

E1 was prepared from D1 following the general procedure reported in Preparative Example 16 Step 2 using methyl iodide for the alkylation. MS (ES) C13H13FN2O3 requires: 264. Found: 265 (M+H)+ and 287 (M+Na)+.