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HuagongsheHuagongshe Chemie-Druckbericht · Nur für Forschungszwecke
HRID 1468331Erstellt: 26. Oktober 2026

(4-Benzyloxy-6-fluoro-3-methyl-naphthalen-2-yl)-acetic acid methyl ester → (6-Fluoro-4-hydroxy-3-methyl-naphthalen-2-yl)-acetic acid methyl ester

https://huagongshe.com/reaction/1468331

Reaktionsgleichung

Beteiligte Stoffe

RolleNameHCIDEinwaage
Edukt(4-Benzyloxy-6-fluoro-3-methyl-naphthalen-2-yl)-acetic acid methyl esterHCID 59326535—
EduktHCID 178418361HCID 178418361—
KatalysatorPalladiumHCID 23938—
LösungsmittelMethanolHCID 887—
Produkt(6-Fluoro-4-hydroxy-3-methyl-naphthalen-2-yl)-acetic acid methyl esterHCID 5932652282%

Reaktionsschritte

To a stirred solution of (4-benzyloxy-6-fluoro-3-methyl-naphthalen-2-yl)-acetic acid methyl ester (15.8 g, 46.7 mmol) in MeOH (150 mL) was added 10% palladium on carbon (2.4 g). The resulting mixture was vigorously stirred under a balloon of hydrogen overnight. The reaction mixture was filtered through celite. The filtrate was concentrated to give the crude product, which was purified by silica gel chromatography (10% ethyl acetate in hexanes) to yield (6-fluoro-4-hydroxy-3-methyl-naphthalen-2-yl)-acetic acid methyl ester (9.5 g, 82%) as a white solid. MS calcd. for C14H14FO3 [(M+H)+] 249, obsd. 249.1.

Herkunft & Nachweise

DOI10.6084/m9.figshare.5104873.v1
PatentnummerUS09000044B2
Quelldatensatzuspto-grants-2015_04
ORD IDord-3124f2a56bee4112acbdc6cfbd639780
Quellennotizuspto-grants-2015_04