HRID1472456

反应详情

EQUATION

反应方程式

HRID 1472456 的结构方程式

AUXILIARIES

试剂、催化剂与溶剂

2

CONDITIONS

反应条件

温度
80 °C

PROCEDURE

实验过程

A vial was charged with 2-fluoropyridin-3-ylboronic acid (0.094 g, 0.667 mmol), PdCl2(dppf)-CH2Cl2-adduct (0.026 g, 0.032 mmol), (S)-3-bromo-7-iodo-2′,6′-dihydrospiro[chromeno[2,3-b]pyridine-5,3′-[1,4]oxazin]-5′-amine (0.300 g, 0.635 mmol), and potassium carbonate (0.351 g, 2.54 mmol). Dioxane (3.5 mL) and water (1.5 mL) were added. The vial was flushed with argon, sealed and heated to 80° C. for 1 hour. The reaction mixture was then diluted with EtOAc, dried over MgSO4 and concentrated. Purification of the crude residue by column chromatography [0-80% (90:10:1 DCM/MeOH/NH4OH)/DCM] gave (S)-3-bromo-7-(2-fluoropyridin-3-yl)-2′,6′-dihydrospiro[chromeno[2,3-b]pyridine-5,3′-[1,4]oxazin]-5′-amine (0.202 g, 0.458 mmol) Step 2: A vial was charged with (R)-3-fluoropyrrolidine HCl (0.021 g, 0.170 mmol), (S)-3-bromo-7-(2-fluoropyridin-3-yl)-2′,6′-dihydrospiro[chromeno[2,3-b]pyridine-5,3′-[1,4]oxazin]-5′-amine (0.050 g, 0.113 mmol) and RuPhos palladacycle (9.05 mg, 0.011 mmol). THF (1 mL) and LiHMDS (1N in THF; 0.567 mL, 0.567 mmol) were added, and the reaction mixture was allowed to stir at RT overnight. Additional RuPhos palladacycle (9.05 mg, 0.011 mmol) and LiHMDS solution (0.567 mL, 0.567 mmol) were added, and the reaction mixture was heated to 45° C. for 2 hours. The reaction mixture was then quenched with MeOH and concentrated under reduced pressure. Purification of the crude residue by column chromatography [0-100% (90:10:1 DCM/MeOH/NH4OH)/DCM] gave (S)-7-(2-fluoropyridin-3-yl)-3-((R)-3-fluoropyrrolidin-1-yl)-2′,6′-dihydrospiro[chromeno[2,3-b]pyridine-5,3′-[1,4]oxazin]-5′-amine (0.018 g, 0.040 mmol, 35.3% yield).

WORKUP

后处理

  1. customThe vial was flushed with argon
  2. customsealed
  3. additionThe reaction mixture was then diluted with EtOAc
  4. dry with materialdried over MgSO4
  5. concentrationconcentrated
  6. customPurification of the crude residue by column chromatography [0-80% (90:10:1 DCM/MeOH/NH4OH)/DCM]