4-Fluorophenol → HCID 59346670, compound
Reaction equation
[F:1][C:2]1[CH:7]=[CH:6][C:5]([OH:8])=[CH:4][CH:3]=1.Br[CH2:10][CH:11]([O:14][CH3:15])[O:12][CH3:13].C([O-])([O-])=O.[K+].[K+]>C(#N)C>[CH3:13][O:12][CH:11]([O:14][CH3:15])[CH2:10][O:8][C:5]1[CH:6]=[CH:7][C:2]([F:1])=[CH:3][CH:4]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
Dissolve 4-fluorophenol (5.5 g, 49.1 mmol) in acetonitrile (49 mL) and treat the solution with 2-bromo-1,1-dimethoxyethane (11.6 mL, 98.1 mmol) and K2CO3 (16.95 g, 122.7 mmol). Heat the solution to reflux with stirring for five days. Filter the mixture, and concentrate the filtrate under reduced pressure. Subject the resulting crude material to silica gel chromatography eluting with a gradient of 0% to 50% EtOAc/hexanes. Concentrate the fractions containing the desired product under reduced pressure to furnish the title compound as a colorless oil (5.85 g, 60% yield). Mass spectrum (m/z) 218 (M+NH4)+, 223 (M+Na)+.
Workup
- temperatureHeat the solution
- temperatureto reflux
- filtrationFilter the mixture
- concentrationconcentrate the filtrate under reduced pressure
- washeluting with a gradient of 0% to 50% EtOAc/hexanes
- concentrationConcentrate the fractions
- additioncontaining the desired product under reduced pressure
Sources & evidence
- ORD record
- ord-b0745f92450247238ec72e8e948c144c
- Source dataset
- uspto-grants-2016_08
- Patent number
- US09402838B2
Reaction notes
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