HRID14772

反应详情

EQUATION

反应方程式

HRID 14772 的结构方程式

REACTANTS

反应物

2

结构：NCCc1ccncc1

4-Pyridineethanamine

C7H10N2

结构：O=Cc1cccc(-c2ccnc(Cl)n2)c1

未命名化合物

PRODUCTS

生成物

1

结构：Clc1nccc(-c2cccc(CNCCc3ccncc3)c2)n1

未命名化合物

PROCEDURE

实验过程

Intermediate 1 was coupled with 2-pyridin-4-yl-ethylamine following procedure B. LC-MS showed the product had the expected M+H+ of 325.