HRID1482124

反应详情

EQUATION

反应方程式

REACTANTS

反应物

HCID4311764

Sodium borohydride (Na(BH4))

H4BNa

结构：COC(=O)[C@@H](OC(C)(C)C)c1c(C)c(C=O)c2nc3cn2c1N1CCC(C)(CC1)OCCCC[C@H](C)Oc1ccc(F)cc1-c1cccc-3c1

HCID118316355

未命名化合物

PRODUCTS

生成物

HCID118316357

未命名化合物

AUXILIARIES

试剂、催化剂与溶剂

溶剂HCID887

Methanol

CH4O

PROCEDURE

实验过程

Methyl(2S)-2-(tert-butoxy)-2-[(22S)-17-fluoro-5-formyl-4,22,28-trimethyl-21,27-dioxa-1,7,34-triazahexacyclo[26.2.2.16,9.110,14.02,7.015,20]tetratriaconta-2,4,6(34),8,10(33),11,13,15(20),16,18-decaen-3-yl]acetate (15 mg, 0.022 mmol, 1.0 equiv) was dissolved in MeOH (437 μl). To this solution was added sodium borohydride (3.31 mg, 0.087 mmol, 4.0 equiv) and stirred at r.t. The solution turned to colorless immediately. It was stirred for ten minutes and quenched by water, extracted by Ethyl Acetate. The organic layer was concentrated to give the pure enough product for the next reaction.

WORKUP

后处理

stirringIt was stirred for ten minutes
customquenched by water
extractionextracted by Ethyl Acetate
concentrationThe organic layer was concentrated
customto give the pure enough product
customfor the next reaction

来源与证据

来源类型: Open Reaction Database
ORD 记录: ord-42f8af2a638e483b952114dd3880d2d7
来源数据集: uspto-grants-2016_08
DOI: 10.6084/m9.figshare.5104873.v1
专利: US09409922B2
来源说明: uspto-grants-2016_08

反应 SMILES

[C:1]([O:5][C@@H:6]([C:11]1[C:40]([CH3:41])=[C:39]([CH:42]=[O:43])[C:38]2=[N:44][C:35]3=[CH:36][N:37]2[C:12]=1[N:13]1[CH2:49][CH2:48][C:16]([CH3:50])([O:17][CH2:18][CH2:19][CH2:20][CH2:21][C@H:22]([CH3:47])[O:23][C:24]2[CH:25]=[CH:26][C:27]([F:46])=[CH:28][C:29]=2[C:30]2[CH:45]=[C:34]3[CH:33]=[CH:32][CH:31]=2)[CH2:15][CH2:14]1)[C:7]([O:9][CH3:10])=[O:8])([CH3:4])([CH3:3])[CH3:2].[BH4-].[Na+]>CO>[C:1]([O:5][C@@H:6]([C:11]1[C:40]([CH3:41])=[C:39]([CH2:42][OH:43])[C:38]2=[N:44][C:35]3=[CH:36][N:37]2[C:12]=1[N:13]1[CH2:14][CH2:15][C:16]([CH3:50])([O:17][CH2:18][CH2:19][CH2:20][CH2:21][C@H:22]([CH3:47])[O:23][C:24]2[CH:25]=[CH:26][C:27]([F:46])=[CH:28][C:29]=2[C:30]2[CH:45]=[C:34]3[CH:33]=[CH:32][CH:31]=2)[CH2:48][CH2:49]1)[C:7]([O:9][CH3:10])=[O:8])([CH3:4])([CH3:2])[CH3:3]