Methyl iodide → HCID 86744864, compound

HRID 1494196Notes

Reaction equation

HRID 1494196 reaction equation
[F:1][C@:2]12[C@@H:30]([OH:31])[CH2:29][C@@:28]3([CH3:32])[C@@H:12]([CH2:13][C@@H:14]([CH3:34])[C@:15]3([OH:33])[C:16](=[O:27])[CH2:17][O:18][C:19]([C:21]3[CH:22]=[N:23][CH:24]=[CH:25][CH:26]=3)=[O:20])[C@@H:11]1[CH2:10][CH2:9][C:8]1[C@:3]2([CH3:36])[CH:4]=[CH:5][C:6](=[O:35])[CH:7]=1.[CH3:37][I:38]>CC(C)=O>[I-:38].[CH3:37][N+:23]1[CH:24]=[CH:25][CH:26]=[C:21]([C:19]([O:18][CH2:17][C:16](=[O:27])[C@:15]2([OH:33])[C@:28]3([CH3:32])[C@H:12]([C@H:11]4[C@:2]([F:1])([C@@H:30]([OH:31])[CH2:29]3)[C@:3]3([CH3:36])[C:8](=[CH:7][C:6](=[O:35])[CH:5]=[CH:4]3)[CH2:9][CH2:10]4)[CH2:13][C@H:14]2[CH3:34])=[O:20])[CH:22]=1

Participants

4

Reactant 2

HCID 6328Methyl iodideHCID 67675462HCID 67675462, compound

Product 1

HCID 86744864HCID 86744864, compoundYield 56%

Reagents, catalysts & solvents 1

HCID 180AcetoneSolvent

Procedure

The product of Example 116 (0.74 g, 1.5 mmol) was dissolved in 50 mL of acetone to which 2 mL of methyl iodide was added. A small amount (10 mL) of CH3NO3 was subsequently added to increase solubility. The reaction was allowed to proceed for 2 days, then the solid was collected to give 0.54 g (56% yield) of the title compound melting at 218°-221° C. and having the formula ##STR145## The structure of the product was confirmed by elemental analysis.

Workup

  1. additionwas added
  2. temperatureto increase solubility
  3. customthe solid was collected

Sources & evidence

ORD record
ord-449d2156dbd64dada6c96cd9fa509819
Source dataset
uspto-grants-1991_06
Patent number
US05024998

Reaction notes

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