huagongshe.com
HRID1508428

反应详情

EQUATION

反应方程式

HRID 1508428 的结构方程式

REACTANTS

反应物

4
结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：CCOC(=O)C(=O)Cc1ccccc1Br
HCID18370522

未命名化合物

结构：CCOC(=O)/C(=C/c1ccccc1F)O[C@H]1O[C@@H](COC(C)=O)[C@H](OC(C)=O)[C@@H](OC(C)=O)[C@@H]1OC(C)=O
HCID66980300

未命名化合物

结构：CC(=O)OC[C@H]1O[C@H](O)[C@H](OC(C)=O)[C@@H](OC(C)=O)[C@@H]1OC(C)=O.[Br-]
HCID86702362

未命名化合物

PRODUCTS

生成物

1
结构：CCOC(=O)/C(=C/c1ccccc1Br)O[C@H]1O[C@@H](COC(C)=O)[C@H](OC(C)=O)[C@@H](OC(C)=O)[C@@H]1OC(C)=O
HCID66980304

未命名化合物

收率 17%

PROCEDURE

实验过程

The title compound was prepared as described for C4 using ethyl 3-(2-bromophenyl)-2-oxopropanoate B8 (100 mg, 0.369 mmol), sodium hydride (9.74 mg, 0.406 mmol) and 2,3,4,6 tetra-O-acetyl-α-D-glucose bromide (152 mg, 0.369 mmol). The resulting compound was isolated in the form of white solid in 17% yield.

WORKUP

后处理

  1. customThe resulting compound was isolated in the form of white solid in 17% yield