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HRID1508443

反应详情

EQUATION

反应方程式

HRID 1508443 的结构方程式

REACTANTS

反应物

4
结构：[H-].[Na+]
HCID24758

Sodium hydride

HNa

结构：CCOC(=O)C(=O)Cc1cccc(C)c1
HCID18370163

未命名化合物

结构：CCOC(=O)/C(=C/c1ccccc1F)O[C@H]1O[C@@H](COC(C)=O)[C@H](OC(C)=O)[C@@H](OC(C)=O)[C@@H]1OC(C)=O
HCID66980300

未命名化合物

结构：CC(=O)OC[C@H]1O[C@H](O)[C@H](OC(C)=O)[C@@H](OC(C)=O)[C@@H]1OC(C)=O.[Br-]
HCID86702362

未命名化合物

PRODUCTS

生成物

1
结构：CCOC(=O)/C(=C/c1cccc(C)c1)O[C@H]1O[C@@H](COC(C)=O)[C@H](OC(C)=O)[C@@H](OC(C)=O)[C@@H]1OC(C)=O
HCID66980200

未命名化合物

收率 19%

PROCEDURE

实验过程

The title compound was prepared as described for C4 using ethyl 3-(3-methylphenyl)-2-oxopropanoate B18 (100 mg, 0.485 mmol), sodium hydride (11.64 mg, 0.485 mmol) and 2,3,4,6-tetra-O-acetyl-α-D-glucose bromide (199 mg, 0.485 mmol). The compound was isolated in the form of white solid in 19% yield.

WORKUP

后处理

  1. customThe compound was isolated in the form of white solid in 19% yield