Sodium Hydroxide → HCID 89501036, compound

HRID 1525359Notes

Reaction equation

HRID 1525359 reaction equation
[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([O:12]C)=[O:11])[CH:7]=1.[OH-].[Na+]>CO.C1COCC1>[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([OH:12])=[O:11])[CH:7]=1

Participants

5

Procedure

To Intermediate 5C (5 g, 17.7 mmol) in MeOH (50 mL) and THF (25 mL) was added 10% NaOH solution (25 mL). After 2 h, the reaction was concentrated and the residue was diluted with H2O. The pH was adjusted to 2 to 3 with 1.5 N HCl and the resultant solid was filtered and washed with petroleum ether to afford 2 g of Intermediate 5. MS (ESI) m/z: 269.0 (M+H)+.

Workup

  1. concentrationthe reaction was concentrated
  2. additionthe residue was diluted with H2O
  3. filtrationthe resultant solid was filtered
  4. washwashed with petroleum ether

Sources & evidence

ORD record
ord-f113eadd17b046029e4aaa97ee2043d0
Source dataset
uspto-grants-2015_07
Patent number
US09079929B2

Reaction notes

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