Potassium Iodide → HCID 15030073, compound

HRID 1533912Notes

Reaction equation

HRID 1533912 reaction equation
[CH3:1][C:2]1[CH:7]=[CH:6][C:5]([N:8]2[CH2:13][CH2:12][NH:11][CH2:10][CH2:9]2)=[CH:4][CH:3]=1.Cl[CH2:15][CH2:16][CH:17]1[O:21][C:20](=[O:22])[N:19]([CH3:23])[CH2:18]1.C(=O)([O-])[O-].[Na+].[Na+].[I-].[K+]>C(O)CCC.CC(O)C>[CH3:23][N:19]1[CH2:18][CH:17]([CH2:16][CH2:15][N:11]2[CH2:12][CH2:13][N:8]([C:5]3[CH:4]=[CH:3][C:2]([CH3:1])=[CH:7][CH:6]=3)[CH2:9][CH2:10]2)[O:21][C:20]1=[O:22]

Participants

7

Reactant 4

HCID 4875Potassium IodideHCID 10340Sodium CarbonateHCID 831131-(p-Tolyl)piperazineHCID 146987465-(2-Chloro-ethyl)-3-methyl-oxazolidin-2-one

Product 1

HCID 15030073HCID 15030073, compoundYield 69.2%

Reagents, catalysts & solvents 2

HCID 2631-ButanolSolventHCID 3776IsopropanolSolvent

Procedure

This compound was prepared according to the procedure of Example 2. A mixture of 3.5 g (0.02 mol) of 1-(4-methylphenyl)piperazine, 3.3 g (0.02 mol) of 5-(2-chloroethyl)-3-methyl-2-oxazolidinone, 6.4 g (0.06 mol) of anhydrous sodium carbonate and 0.3 g of potassium iodide in 100 mL of 1-butanol gave 4.2 g (69%) of white solid, mp 96°-97° C. (2-propanol).

Workup

  1. customThis compound was prepared

Sources & evidence

ORD record
ord-1b4fa5747e5c412fae385767b68b5782
Source dataset
uspto-grants-1992_02
Patent number
US05086055

Reaction notes

Loading…