Formaldehyde formic acid → N-methyl-N-(3-phenylpropyl)-4-phenylbutylamine

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Reaction Steps

Phenylbutyric acid chloride and 3-phenylpropylamine were reacted to form the amide which next was reduced with diborane to give N-(3-phenylpropyl)-4-phenylbutylamine. The amine was methylated with formic acid/formaldehyde to form the starting material, N-methyl-N-(3-phenylpropyl)-4-phenylbutylamine. 5.3 Grams of N-methyl-N-(3-phenylpropyl)phenylbutylamine was dissolved in 150 ml. of diethyl ether in a 300 ml. round bottom flask. Methyl bromide gas was bubbled through the mixture until it was saturated The mixture was stirred at room temperature for 3 days. The solid material which had formed was collected by filtration and crystallized from 100 ml. methyl ethyl ketone and ethyl acetate to yield 5.08 g. of N,N-dimethyl-N-phenylpropyl-phenylbutylammonium bromide. M.P. 81°-83° C.

Provenance & Evidence