Hydrochloric Acid → HCID 15870513, compound
Reaction equation
[CH3:1][O:2][C:3]1[CH:4]=[C:5]([C:9]2[S:13][C:12]3[CH:14]=[CH:15][CH:16]=[CH:17][C:11]=3[C:10]=2[O:18][C:19]2[CH:24]=[CH:23][C:22]([O:25]CC3C=CC=CC=3)=[CH:21][CH:20]=2)[CH:6]=[CH:7][CH:8]=1.Cl>CCO.CCOC(C)=O.[Pd]>[CH3:1][O:2][C:3]1[CH:4]=[C:5]([C:9]2[S:13][C:12]3[CH:14]=[CH:15][CH:16]=[CH:17][C:11]=3[C:10]=2[O:18][C:19]2[CH:20]=[CH:21][C:22]([OH:25])=[CH:23][CH:24]=2)[CH:6]=[CH:7][CH:8]=1Participants
Reactant 2
Product 1
Reagents, catalysts & solvents 2
Procedure
To a solution of 2-(3-methoxyphenyl)-3-(4-benzyloxyphenoxy)benzo[b]thiophene (8.30 g, 29.0 mmol) in 1:1 (100 mL) EtOH/EtOAc in a Paar bottle was added 10% Pd/C (4.0 g). To this suspension was added 2.0 mL of con. HCl. The resulting mixture was hydrogenated at 40 psi for 20 min. The reaction was filtered through Celite®, and the filtrate was concentrated in vacuo to an oil. The crude product was partitioned between CHCl3 and sat. NaHCO3 solution. The layers were separated, and the organic was dried (Na2SO4) and concentrated in vacuo to give 3.8 g (61%) of 2-(3-methoxyphenyl)-3-(4-hydroxyphenoxy)benzo[b]thiophene as an amber brown foam. 1H NMR (CDCl3) d 7.80 (d, J=8.1 Hz, 1H), 7.46-7.27 (m, 6H), 6.88-6.84 (m, 3H), 6.71-6.74 (m, 2H), 4.57 (s, 1H), 3.77 (s, 3H). FD mass spec: 348. Anal. Calcd. for C21H16O3S: C, 72.39; H, 4.63. Found: C, 72.10; H, 4.63.
Workup
- additionTo this suspension was added 2.0 mL of con
- filtrationThe reaction was filtered through Celite®
- concentrationthe filtrate was concentrated in vacuo to an oil
- customThe crude product was partitioned between CHCl3 and sat. NaHCO3 solution
- customThe layers were separated
- dry with materialthe organic was dried (Na2SO4)
- concentrationconcentrated in vacuo
Sources & evidence
- ORD record
- ord-04d40b6b1b5d498e922bab927f8e9201
- Source dataset
- uspto-grants-1999_11
- Patent number
- US05977098
Reaction notes
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