Methacrylic Acid → 2-Ethoxyethyl methacrylate

HRID 1604197Notes

Reaction equation

HRID 1604197 reaction equation
C1(C(C2CCCCCCCCC2)=C(C2CCCCCCCCC2)C([O-])=O)CCCCCCCCC1.C(O)(=O)C(C)=C.[C:42]([O:47][CH2:48][CH2:49][O:50][CH2:51][CH2:52]OC(CCC)=O)(=[O:46])[C:43]([CH3:45])=[CH2:44]>>[C:42]([O:47][CH2:48][CH2:49][O:50][CH2:51][CH3:52])(=[O:46])[C:43]([CH3:45])=[CH2:44]

Participants

4

Reactant 3

HCID 4093Methacrylic AcidHCID 19602210HCID 19602210, compoundHCID 54303211HCID 54303211, compound

Product 1

HCID 714042-Ethoxyethyl methacrylate

Procedure

In the same way as the embodiment 1, synthesis of terpolymer was performed using 3.4 grams (0.0166 mols) of tricyclodecanylacrylate, 0.7 grams (0.0083 mols) of methacrylic acid, and 4 grams (0.0166 mols) of propylcarbonyloxyethoxyethyl methacrylate, which is a compound having been obtained in the synthesis example 10, in place of ethoxyethyl methacrylate. As a result, there was obtained 4.86 grams of poly (tricyclodecylacrylate-propylcarbonyloxyethoxyethyl methacrylate-methacrylic acid). The yield was 60%.

Workup

  1. customIn the same way as the embodiment 1, synthesis of terpolymer

Sources & evidence

ORD record
ord-656e0480a59643fe93a5df4423d572f6
Source dataset
uspto-grants-1999_11
Patent number
US05994025

Reaction notes

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