Sulfuric Acid → Acetic Anhydride
Reaction equation
[OH:1]S(O)(=O)=O.[OH-].[Na+:7].[CH2:8]([O:10][C:11](=[O:21])[C@H:12](CCSC)NC(=O)C)[CH3:9].C(OCC)(=[O:24])C>C(O)(=O)C>[C:11]([O:10][C:8](=[O:24])[CH3:9])(=[O:21])[CH3:12].[OH-:1].[Na+:7]Participants
7
Reactant 4
Product 2
Reagents, catalysts & solvents 1
Procedure
To this solution was added with stirring sufficient anhydrous H2SO4 to neutralize the NaOH and render the solution slightly acidic. Under these conditions the N-acetyl-L-methionine was converted to N-acetyl-L-methionine ethyl ester. The remaining ethanol and ethyl acetate (formed from the reaction of residual acetic acid and acetic anhydride with NaOH) was removed by warming the mixture under vacuum. The remaining mixture was slurried with cholorform and filtered to removed sodium sulfate salts. The ester-chloroform solution was then water washed to remove any remaining salts. The resulting ester-chloroform solution was then warmed under vacuum to remove the chloroform. The resulting material was N-acetyl-L-methionine ethyl ester.
Workup
- additionTo this solution was added
Sources & evidence
- ORD record
- ord-e851f7604cd54400a5aabb33d9d54da7
- Source dataset
- uspto-grants-1976_04
- Patent number
- US03952115
Reaction notes
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