4-Fluorobenzoyl chloride → HCID 22258168, compound
Reaction equation
CC1NC2CCCCC=2N=1.FC1C=CC(C(Cl)=O)=CC=1.F[C:22]1[CH:27]=[C:26]([F:28])[CH:25]=[CH:24][C:23]=1[C:29](=[O:40])[CH2:30][C:31]1[NH:35][C:34]2[CH2:36][CH2:37][CH2:38][CH2:39][C:33]=2[N:32]=1>C(#N)C>[F:28][C:26]1[CH:25]=[CH:24][C:23]([C:29](=[O:40])[CH2:30][C:31]2[NH:32][C:33]3[CH2:39][CH2:38][CH2:37][CH2:36][C:34]=3[N:35]=2)=[CH:22][CH:27]=1Participants
5
Reactant 3
Product 1
Reagents, catalysts & solvents 1
Procedure
The compound is prepared as described in example XXXXIII with 2.00 g (14.68 mmol) 2-methyl-4,5,6,7-tetrahydro-1H-benzimidazole, 6.98 g (44.05 mmol) of 4-fluorobenzoyl chloride and 4.90 g (48.42 mmol) of TEA in 50 ml acetonitrile. The crude intermediate is directly transformed into 1-(2,4-Difluorophenyl)-2-(4,5,6,7-tetrahydro-1H-benzimidazol-2-yl)-ethanone to yield 737 mg (10.7% of th.).
Workup
- customThe compound is prepared
- customto yield 737 mg (10.7% of th.)
Sources & evidence
- ORD record
- ord-6ed5f68f1fe6407394fb7d22d9155326
- Source dataset
- uspto-grants-2006_01
- Patent number
- US06984646B2
Reaction notes
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